x^2+20x-3149=0

Solution for x^2+20x-3149=0 equation:

x^2+20x-3149=0

a = 1; b = 20; c = -3149;
Δ = b2-4ac
Δ = 202-4·1·(-3149)
Δ = 12996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12996}=114$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-114}{2*1}=\frac{-134}{2}
=-67
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+114}{2*1}=\frac{94}{2}
=47
$